1995A - Diagonals - CodeForces Solution

2-sat binary search bitmasks brute force chinese remainder theorem combinatorics constructive algorithms data structures expression parsing fft flows greedy implementation math meet-in-the-middle string suffix structures ternary search trees

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Python Code: 

gg=int(input())

for r in range(0,gg):
  n, k = input().split()
  n = int(n)
  k = int(k)
  s = 0
  t = 0
  if k > 0:
    t += n
    s += 1
    n -= 1
    if t != k and k> n:
        while 2*n + t < k and n> 0:
          t += 2*n
          s += 2
          n -= 1

        if n + t < k:
            t += 2*n
            s += 2
            n -= 1
        else:
            t += n
            s += 1
            n -= 1

    print(s)
  else:
    print(s)


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